WebbAnswer (1 of 2): Well, what does the old buffer equation say….? pH=pK_{a}+log_{10}(\dfrac{[NH_{3}]}{[NH_{4}^{+}]}) pK_{a}=9.24 for ammonium … and the pH of the buffer will be slightly elevated above this value given that ammonia concentration is slightly greater than ammonium … remember to adju... Webb25 mL of 0.2 M KI + 48.00 mL 0.2 M KNO3 + 1 mL 0.4 M Na2S2O3 + 1 mL starch + 25 mL 0.2 M (NH4)2S2O8 + 1 drop EDTA How do I calculate the. Chemistry; asked by Louise; 633 views; 0 answers; When used correctly, the volumetric flasks in the first year chemistry laboratory will produce a solution volume of 250.00 ± 0.12 mL.
0.2M (NH4)2S2O8 - questions.llc
WebbYou'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading Question: 1) What is the ph … Webb1) What is the ph of a 0.005 M , solution of h2so4? ka2=1.2x10^-2 of HSo4- Expert Answer 100% (3 ratings) Since the Ka1 value of H2SO4 is very high, all of the H2SO4 are dissociated into H+ and HSO4- (aq). Now for the dissociatio … View the full answer Previous question Next question bing bot chat
What is the pH using the Hasselbalch equation of a buffer solution …
Webb29 aug. 2024 · Solution Part a. Dissolving 1 mol of Al (NO 3) 3 in water dissociates into 1 mol Al 3+ and 3 mol NO 3- by the reaction: Al (NO 3) 3 (s) → Al 3+ (aq) + 3 NO 3- (aq) Therefore: concentration of Al 3+ = 1.0 M concentration of NO 3- = 3.0 M Part b. K 2 CrO 4 dissociates in water by the reaction: K 2 CrO 4 → 2 K + (aq) + CrO 42- WebbQ. 100 mL of 0.005 M H2SO4 is diluted to 1 L. The resulting pH will be . Q. 100 ml of 0.1 M H2SO4 diluted 900 ml of water find the pH of resultant solution. Q. 100mL solution of … WebbQ: A solution is 0.25 M HNO2 and 0.24 M NaNO2. What is the pH of the solution. (Ka(HNO2) = 4.5x10-4… A: Here is a solution of weak acid and its conjugate base salt. So … bing boolean operators